Answer:
H0 : μ = 0.75
H1 : μ > 0.75
Step-by-step explanation:
Given :
Sample size, n = 125
x = 99
Phat = x / n = 99 / 125 = 0.792
Population proportion, P = 0.75
The hypothesis :
Null hypothesis :
H0 : μ = 0.75
Alternative hypothesis ;
Egates the null hypothesis ; since the sample proportion is greater than the the population proportion or claim "; then we use the greater than sign.
H1 : μ > 0.75
In statistics, the number of degrees of freedom is the number of values in the final calculation of a statistic that are free to vary.
The number of independent ways by which a dynamic system can move, without violating any constraint imposed on it, is called number of degrees of freedom.
In other words, the number of degrees of freedom can be defined as the
minimum number of independent coordinates that can specify the position
of the system completely.
<span>
The degree of freedom represents the number of ways in which the expected classes are free to vary in the chi-square goodness-of-fit test.</span>
2x = Twice your age
200 = Two hundred less
> -1 = more than negative
With the information given, your equation would be:
200-2x>-1
Answer:
N = 920(1+0.03)^4t
Step-by-step explanation:
According to the given statement a car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012.
Rate is 12 % annually
rate in quarterly = 12/4= 3%
We will apply the compound interest equation:
N=P( 1+r/n)^nt
N= ending number of cars serviced.
P= the number of cars serviced in 2012,
r = interest rate
n = the number of compoundings per year
t= total number of years.
Number of compoundings for t years = n*t = 4t
Initial number of cars serviced=920
The quarterly rate of growth = n=4
r = 3%
The growth rate = 1.03
Compound period multiplied by number of years = 920(1.03)^4t
Thus N = 920(1+0.03)^4t
N = number of cars serviced after t years...
Answer:
The answer is the option B
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form 
is equal to
in this problem we have
so
substitute in the formula
