For any exponential function, f(x) = abx, the range is the set of real numbers above or below the horizontal asymptote, y = d, but does not include d, the value of the asymptote.
Overall, the steps for algebraically finding the range of a function are:
Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).
Find the domain of g(y), and this will be the range of f(x).
If you can't seem to solve for x, then try graphing the function to find the range.
Answer:
Step-by-step explanation:
For convenience, I labeled some points as shown in the attached picture.
Also, I assume and are tangents to the circle.
- (reflexive property)
- (tangents drawn from a common external point are congruent)
- (right angles are congruent)
Therefore, we know by HL.
Thus, by CPCTC,
This means the measure of minor arc AC is , and thus
Answer:
A
Step-by-step explanation:
This notation says that x+x+x+x+37=69
This can be simplified to say 4x+37=69
Multiples of 2: 2,4,6,8
Multiples of 6:6,12,18,24
Multiples of 12:12,24,36,48
Multiples of 25:25,50,75,100
Further explanation:
A multiple is a number that is obtained by multiplying an integer with that number.
We have to find multiples of given numbers:
So,
<u>1. Multiples of 2</u>
<u>2. Multiples of 6</u>
<u>3. Multiples of 12</u>
<u>4. Multiples of 25</u>
Keywords: Multiples, Non-zero multiples
Learn more about multiples at:
#LearnwithBrainly
a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
Learn more about perimeter of quarter circle on:
brainly.com/question/15976233