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Eva8 [605]
3 years ago
7

Help me pls anyone?

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

m= -2

Step-by-step explanation:

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Find the sun of 5 ,-7 A.-2 B 12 c-35 D 2
hichkok12 [17]

Answer:


Step-by-step explanation:

Solution in given attachment.

8 0
3 years ago
Write the equation of a line that passes through the given point and is parallel to the given line.
monitta

Answer:

  1. y=2x+5
  2. y= 1/3x -4

Step-by-step explanation:

1.

(1,-3)=(x_1,y_1)\\\\y =2x+2\\\\m = 2

Substitute values into point-slope form

y-y_1=m(x-x_1)\\\\y -3 =2(x-(-1))\\\\y-3=2(x+1)\\\\y-3=2x+2\\\\y=2x+2+3\\\\y=2x+5

2.

(18,2) =(x_1,y_1)\\\\3y-x=-12

Arrange equation in slope-intercept form (y=mx+b)and derive slope

3y =x-12\\\\\frac{3y}{3} =\frac{1x}{3} -\frac{12}{3} \\\\y = \frac{1}{3} x -4\\\\m = \frac{1}{3}

Substitute values into point-slope form

y-y_1=m(x-x_1)\\\\\\y-2=\frac{1}{3} (x-18)\\\\y-2=\frac{1}{3} x -6\\\\y=\frac{1}{3} x -6+2\\\\y=\frac{1}{3} x -4

5 0
3 years ago
What are the possible solutions to the equation: x-12 = sqrt x+44
Ainat [17]

possible solutions for equation  x-12 = \sqrt{x+44} is  x=5 , x=20

<u>Step-by-step explanation:</u>

Here we have to find  the possible solutions to the equation: x-12 = sqrt x+44 .Let's find out:

⇒ x-12 = \sqrt{x+44}

⇒ (x-12)^2 = (\sqrt{x+44})^2

⇒ (x^2+144-24x) =x+44

⇒ (x^2+144-24x) -(x+44) =0

⇒ (x^2+100-25x) =0

⇒ x^2-25x+100 =0

⇒ x^2-20x-5x+100 =0

⇒ x(x-20-5(x-20) =0

⇒ (x-5)(x-20)=0

⇒ x-5=0 , x-20=0\\

⇒ x=5 , x=20

Therefore , possible solutions for equation  x-12 = \sqrt{x+44} is  x=5 , x=20

6 0
3 years ago
A person who needs a car for a few weeks while visiting family out of state would most likely choose which of the following?
cupoosta [38]
Whats the options???
5 0
3 years ago
Read 2 more answers
Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9}={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} A={1, 3, 4, 5, 7,
blagie [28]

Answer:

a) A' = [0,2,6,8]

b) (AUB)' = [0,2,6]

c) (AUB')' = [9]

d) A∩B′= [3,5,9]

Step-by-step explanation:

Assuming this problem: "Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} , and B={1, 4, 7, 8} . List the elemetns of the following sets in the increasing order: a) A′=  b) (A∪B)′={ , , }} c) (A∪B′)′={ }} d) A∩B′={ , , }}"

Part a

For this case we just need to find the elements in the universal set that are not in A. And we see that:

A' = [0,2,6,8]

And that represent the complement for A

Part b

For this case we need to find first the Union AUB who are the elements on A or B without repetition and we got:

AUB = [1,3,4,5,7,8,9]

And now the complement for (AUB)' are the elements that are not in AUB but are on the universal set and we got:

(AUB)' = [0,2,6]

Part c

For this case we need to find B' who are the elements on the universal set that are not in B

B' = [0,2,3,5,6,9]

Then we can find the union between AUB' and we got:

AUB' = [0,1,2,3,4,5,6,7,9]

And then the complment is just:

(AUB')' = [9]

Part d

For this case we just need to see the elements in common between A and B' and we got:

A∩B′= [3,5,9]

6 0
4 years ago
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