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vaieri [72.5K]
3 years ago
8

I need help quick I can’t fail I need a good grade pls help

Mathematics
2 answers:
dusya [7]3 years ago
5 0
B I think I am unsure
Over [174]3 years ago
5 0

Answer:

ok I will try and tell you

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A swimming pool already contains
xenn [34]

Answer:

Rate of change = <u>3 gallons/minute</u>

Starting volume = 30 gallons

Step-by-step explanation:

A graph of the pool's water level would be useful.  The slope of the line would represent the rate of change for filling the pool.  It will also help us determine the amount of water that was in the pool to start.  Although it is tempting to say the rate of fill is 45gallons/5 minutes, or 9 gallons/minute, it is not correct.  The pool already started with an unknown volume of water.  The rate of change after 5 minutes, however, can be used.  The problem states it is being added at a constant rate.  Let's find an equation for a line, in the format of y=mx+b, where m is the slope (rate of change) and b is the y-intercept.

We'll let y represent the volume of water in the pool, and x will be the time in minutes.  The y-intercept will give us the amount of water in the pool at the start (x = 0).

The slope can be determined between the two given points:

(5,45) and (30,120):

Slope = Rise/Run [The change in y divided by the change in x].

Rise = (120 - 45) = 75

Run = (30-5) = 25

Slope = 75/25 or 3

The line, so far, becomes y=3x + b

The slope of <u>3 has units of gallons/minute.  It is the rate at which the pool is being filled.</u>

We can find b, the starting volume of water, by using one of the two points in the equation and solving for b:

y=3x + b   [I'll use (5,45)]

45 = 3*(5) + b

<u>b = 30 gallons</u>

<u>The pool had 30 gallons to start (at x = 0(minutes))</u>

See the graph of the line, attached.

6 0
3 years ago
Fifty-six is eight less than twice what number
OverLord2011 [107]
It is twice the number 32
7 0
3 years ago
Read 2 more answers
Find the slope of every line that is parallel to the line on the graph.​
melamori03 [73]

Answer:

-1/5

Step-by-step explanation:

What are parallel lines?

Lines that are parallel never touch. They can extend infinitely and they will still never touch. In order for this to happen the slope of the two lines must be the same. So if we want to find the slope of every line that is parallel to the line on the graph, we simply find the slope of the line of the graph.

Finding the slope

We can find the slope using the following formula:

Slope=\frac{y_2-y_1}{x_2-x_1}

Where the x and y values are derived from any given points on the line (x1,y1) and (x2,y2)

Here the given points are (-5,-1) and (0,-2)

So we have (x1,y1) = (-5,-1) meaning x1 = -5 and y1 = -1

We also have (x2,y2) = (0,-2) meaning x2 = 0 and y2 = -2

Now we plug these values into the formula

Recall formula : Slope=\frac{y_2-y_1}{x_2-x_1}

==> Plug in x1 = -5 , y1 = -1 , x2 = 0 and y2 = -2

Slope=\frac{-2-(-1)}{0-5}

==> simplify numerator and denominator

slope = \frac{1}{-5}

So the slope of the line is -1/5

This means the slope of any parallel line to that line would also have a slope of -1/5

8 0
3 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
Em um posto de combustível, o litro da gasolina estava custando R$2,40.Um cliente gastou R$72,00 para encher o tanque de seu car
Julli [10]

Answer:

english i think u need hekp

7 0
4 years ago
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