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Kipish [7]
3 years ago
6

Use the drop-down menus to describe the key aspects of the function f(x) = –x2 – 2x – 1. The vertex is the . The function is inc

reasing . The function is decreasing . The domain of the function is . The range of the function is
Mathematics
2 answers:
mixer [17]3 years ago
7 0
Let's dissect    <span>f(x) = –x2 – 2x – 1.  

a) This is a quadratic equation whose graph is a parabola that opens down.  
b) The coefficients of x^2, x and 1 are {-1,-2, -1}.


</span>                                                                             
c) Applying the quadratic formula results in

        -(-2) plus or minus sqrt ([-2]^2 - 4(-1)(-1) )
x = ----------------------------------------------------------
                            2(-1)

or x  = + 2 plus or minus sqrt(0)
           --------------------------------- = -1
                        -2       

Actually, we have a double root here:  x is {-1, -1}.

This means that the graph of this parabola touches the x-axis once, at (-1,0), but does not cross that axis.  (-1,0) is also the "root" or "solution" or "x-intercept"

The function is increasing from -infinity up to -1, and decreasing from -1 to positive infinity.

The domain is "the set of all real numbers."

The range is "the set of all real numbers from neg. infinity to zero."  y is never positive.

Please graph this function, so that you can verify this information.
Ierofanga [76]3 years ago
5 0

Answer:

The vertex is (-1, 0),

The function is increasing and decreasing both for different intervals,

The domain of the function is set of all real numbers,

Range is (-∞, 0]

Step-by-step explanation:

Given function,

f(x)=-x^2 - 2x - 1

f(x) = -(x^2 + 2x+1)

f(x) = -(x+1)^2+0

Since, vertex form of a quadratic equation is,

f(x) = a(x-h)^2 + k

Where,

(h, k) is the vertex of the function,

By comparing,

Vertex of the given function = (-1, 0),

A quadratic function with negative leading coefficient is increasing from -∞ to its vertex and decreasing from its vertex to +∞,

Also, domain of a quadratic function is set of all real numbers,

While, quadratic function with negative leading coefficient is maximum at its vertex,

∴ Range = (-∞, 0]

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Firlakuza [10]

Answer:

nhjggggggggggggj

Step-by-step explanation:

5 0
3 years ago
which measurement is closest to the volume of the cone in cubic inches . the height is 7.5 &amp; the radius is 5.62 . show work
Dominik [7]
To find the volume, you would use the formula V=1/3 pi times radius squared times the height. So, you would multiply 1/3 x 3.14 x 5.62^2 x 7.5. This equals approximately 248 cubic inches.
7 0
3 years ago
Find BC if AC = 13 and AB = 10
maxonik [38]

Answer:

BC=3

Step-by-step explanation:

<em>We </em><em>can </em><em>solve </em><em>this </em><em>by </em><em>eliminating</em><em> </em><em>given </em><em>detail </em><em>of </em><em>A.</em>

AC=13 , AB=10

<u>To </u><u>find </u><u>BC,</u><u> </u><u>We </u><u>minus </u><u>A</u><u>C</u><u> </u><u>With </u><u>AB</u>

BC= AC-AB

<u>BC=3</u>

3 Is the final answer

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

7 0
3 years ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
valentina_108 [34]
The answer is  0 < x <span>≤ 7 
</span>
First, we know that width =  x
Which means that length = x +18

So, the possible equation for the Table's area is

X (X + 18)  ≤ 175

X^2 + 18x - 175  <span>≤ </span>0

Next, we need to calculate is by using complete square method
x^2 + 18x + 81 <span>≤ 175 + 81

(x + 9)^2 </span><span>≤ 256

|x + 9| </span><span>≤ sqrt(256)

|x + 9| </span><span>≤ +-16

-16 </span>≤ x + 9 <span>≤ 16

</span>-16 - 9 ≤ x <span>≤ 16 - 9

</span>-25 ≤ x <span>≤ 7

Since the width couldn't be negative, we can change -25 with 0,

so it become
</span> 0 < x ≤ 7 
7 0
3 years ago
What is the solutions of the equation 2 (x+2) ^2-4=28
JulsSmile [24]

Answer:

x = 2            x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

(x+2)^2 = 16

Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

x+2 = ±4

Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4      and x = -2-4

x = 2            x = -6

3 0
3 years ago
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