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guajiro [1.7K]
3 years ago
12

State the solution of the system of linear equation using its grap 6. SOLUTION: ( -2

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

Solution is (2, -1)

Step-by-step explanation:

The lines cross  at the point where x = 2 and y = -1.

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Two column proofs Beginner's
Darina [25.2K]

LETS prove the 2nd part of the Question

Here concept of right angles is used

We can see BA is perp to BD

and BC is perp to BE

We have to prove angle 1 = angle 3

i will denote angle by a

therefore we need to prove a1 = a3

as BA is perp to BD hence angle between them will be 90 degree

a1 + a2 = 90 degree

Similarly BC is perp to BE

a2 + a3 = 90 degree

as both equations add up gives 90 degree so will equate them

a1 + a2 = a2 + a3

which means a1 = a3

Hence Proved

To learn more about Right Angles:

brainly.com/question/7116550

#SPJ1

3 0
1 year ago
Complete the square 4y^2+x+8y+1=0
sammy [17]

Answer: Simple and best practice solution for 4y^2+8y+1=0 equation. ... Begin completing the square. ... Square it (1) and add it to both sides.

Step-by-step explanation: Complete the square for x2+2x x 2 + 2 x.

4 0
2 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
Can u guys tell me what 1/4 + 1/8 is cause im in a bind right now pls
Naily [24]

Answer:

3/8

Step-by-step explanation:

1/4 is equal to 2/8.

2/8 + 1/8 = 3/8

I would appreciate brainliest but if not that's ok!

3 0
3 years ago
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How many texts do you send in one day (teenagers) on average? I need this data for a stats lab!!!!
Masja [62]
Around 70-80 depending on how many people I’m texting
7 0
3 years ago
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