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otez555 [7]
3 years ago
6

Can you help me solve these

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

1. y = 5 - 2x

2. b = a - 3

3. x = 5y - 12

4. c = (12+7d)/3

5. y = (24-4x)/3

6. x = (4 - 3y)/2

Step-by-step explanation:


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Ian is playing video games. For every 11 enemies he defeats, he gets 6 points. If he has 24 points at the end of the game, how m
ohaa [14]

Hi

if he has 24 point he scored 24/ 6 = 4 times

As he score points every 11 ennemies,

He had : 4*11= 44 ennemies.

6 0
2 years ago
What would the equation be for a quadratic equation with a vertex of (-5,-2)?
natta225 [31]
The quadratic equation could be: y=(x+5)^2-2
4 0
3 years ago
Solve.
Ne4ueva [31]

Answer:

x = -6                  x = -1

Step-by-step explanation:

x^2 + 7x + 6 = 0

Factor

What two numbers multiply to 6 and add to 7

6*1 = 6

6+1 = 7

(x+6) (x+1) =0

Using the zero product property

x+6 = 0  x+1 = 0

x+6-6 =0 -6       x+1-1 = 0-1

x = -6                  x = -1

8 0
3 years ago
Use the quadratic formula to solve the equation. <br> x ^2 – 7 x –6 = 0<br> (Show work)
Vika [28.1K]

Given a quadratic equation

ax^2+bx+c=0

the quadratic formula states that the solutions are

x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Plug your values to get

x_{1,2}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1}

Which evaluates to

\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1} = \dfrac{7\pm\sqrt{73}}{2}

So, the two solutions are

x_1 = \dfrac{7+\sqrt{73}}{2},\quad x_2 = \dfrac{7-\sqrt{73}}{2}

5 0
3 years ago
Need answer ASAP plssss
Marysya12 [62]

Answer:

I believe they ate 4/8. 2 apple and 2 banana muffins makes 4. They still have 4 blueberry muffins left. so 4/8

7 0
3 years ago
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