What is the following sum

Mathematics

2 answers:

Doss [256]2 years ago

8 0

Answer:

2nd option is the correct answer

$12{b}^{2} \bigg(\sqrt[3]{2a} \bigg)$

Step-by-step explanation:

$3 {b}^{2} \bigg( \sqrt[3]{54a} \bigg) + 3 \bigg( \sqrt[3]{2a {b}^{6} } \bigg) \\ \\ = 3 {b}^{2} \bigg( \sqrt[3]{27 \times 2a} \bigg) + 3 \bigg( \sqrt[3]{2a {( {b}^{2} )}^{3} } \bigg) \\ \\ = 3 {b}^{2} \bigg( \sqrt[3]{ {3}^{3} \times 2a} \bigg) + 3 \bigg({\sqrt[3]{{( {b}^{2} )}^{3}2a} } \bigg) \\ \\ = 3 {b}^{2} \times 3 \sqrt[ 3]{2a} + 3 {b}^{2} \sqrt[3]{2a} \\ \\ = 9 {b}^{2} \sqrt[ 3]{2a} + 3 {b}^{2} \sqrt[3]{2a} \\ \\ = 12{b}^{2} \bigg(\sqrt[3]{2a} \bigg)$

lisabon 2012 [21]2 years ago

6 0

Answer:

second option: 12b²(∛2a)

Step-by-step explanation:

you can break $\sqrt[3]{54a}$ into $\sqrt[3]{3^3(2a)}$ which equals 3 $\sqrt[3]{2a}$

you can break $\sqrt[3]{2ab^6}$ into $\sqrt[3]{2ab^3b^3}$ which equals b² $\sqrt[3]{2a}$

now we can simplify: (3b² · 3 $\sqrt[3]{2a}$ ) + 3b² $\sqrt[3]{2a}$ = 9b² $\sqrt[3]{2a}$ + 3b² $\sqrt[3]{2a}$

this equals 12b² $\sqrt[3]{2a}$

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