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skad [1K]
3 years ago
9

A bird can fly at an elevation of 6400 meters. A fish can swim at a depth of 500 meters. What is the difference between the bird

s elevation and the fish’s depth
Mathematics
2 answers:
never [62]3 years ago
5 0

The depth can be represented as

d = b - f where

d = depth

b = bird height

f = fish depth

d = 6400 - (- 500)

d = 6400 + 500

d = 6900 m

Answer: <em><u>The difference in the elevation and depth of the bird and fish is 6900 m</u></em>

Inessa [10]3 years ago
4 0

5900 is  the answer because

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2.) You are buying gifts for 10 people. You decide to buy each person either a CD or a
Katena32 [7]

Answer:

a. The number of DVDs is 10 - c

b. The cost of the CDs is 12c

c. The cost of the DVDs is 20(10 - c)

d. The total cost of all gifts is 200 - 8c

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- You are buying gifts for 10 people

# You will buy 10 gifts

- The gifts are CD or DVD

# The total numbers of CDs and DVDs is 10

- The cost of each CD is $12 and the cost of each DVD is $20

a.

# c is the number of CDs

∵ You buy c CDs

∵ The total numbers of CDs and DVDs is 10 as we said up

∴ c + the numbers of DVDs = 10

- Subtract c from both sides

∴ The number of DVDs = 10 - c

* The number of DVDs is 10 - c

b.

∵ The number if CDs is c

∵ The cost of each CD is $12

∴ The cost of the CDs = 12 × c = 12c

* The cost of the CDs is 12c

c.

∵ The number of DVDs is 10 - c

∵ The cost of each DVD is $20

∴ The cost of the DVDs = 20(10 - c)

* The cost of the DVDs is 20(10 - c)

d.

∵ The cost of the CDs is 12c

∵ The cost of the DVDs is 20(10 - c)

- The total cost of all the gifts is the sum of the costs of CDs and DVDs

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- Multiply the bracket by 20

∵ 20(10 - c) = 100(2) - 20(c) = 200 - 20c

∴ The total cost of all gifts = 12c + 200 - 20c

- Add like terms

∴ The total cost of all gifts = 200 - 8c

* The total cost of all gifts is 200 - 8c

3 0
3 years ago
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