3 years ago

Y = -x^2 + 5 -x + y = 3 Solve algebraically pleaseee help!!!

1 answer:

4 0

2.37 I’m pretty sure

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Kamila [148]

Answer:

it depends on the people and their life style

Step-by-step explanation:

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3 years ago

Tasya [4]

Answer: 120

Step-by-step explanation:

The total number of digits from 1 to 9 = 10

The number of digits from less than 5 (0,1,2,3,4)=5

Since repetition is not allowed so we use Permutations , then the number of 3-digit different codes will be formed :-

$^5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5\times4\times3\times2!}{2!}=5\times4\times3=60$

The number of digits from greater than 4 (5,6,7,8,9)=5

Similarly, Number of 3-digit different codes will be formed :-

$^5P_3=60$

Hence, the required number of 3-digit different codes = 60+60=120

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3 years ago

ss7ja [257]

6000. All you have to do is multiply lengthxwidthxheigth

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3 years ago

Genrish500 [490]

Answer:

Step-by-step explanation:

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3 years ago

telo118 [61]

Answer:

yes I try but not any solution come

please mark me brainliest and follow me my friend.

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3 years ago