Y = -x^2 + 5 -x + y = 3 Solve algebraically pleaseee help!!!

The function f(t) = 20 sin (pi over 5t) + 12 models the temperature of a periodic chemical reaction where t represents time in h

gregori [183]

The answer for the exercise shown above is the second option, which is: Maximum: 32°; minimum: −8°; period: 10 hours.
The explanation is shown below:
 You can make a graph of the function given in the problem above: f(t)=20Sin(π/5t)+12.
As you can see in the graph, the maximum point is at 32 over the y-axis, and the minimum is at -8.
The lenght of the repeating pattern of the function (Its period) is 10.

6 0

3 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) Center of the circle is translated 4 units to the right (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) Reflection over the x-axis:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

4 0

3 years ago

Which parallelogram has an area of 60 square units? Select the correct

faust18 [17]

Wait what is what which number goes to what letter

8 0

3 years ago

Which linear equations has a slope of -3 and a y intercept of 4

Pavlova-9 [17]

This would be represented by the function Y = -3x + 4 C:

just remember that your slope is your X value, and on a graph it is your rise over run. since -3 is your slope, you go down -3(your rise, you go down since it is negative) and over one. its a whole number instead of a fraction because -3/1 is simplified to -3. Your Y intercept is the added number in the end of the equation. Basically they are your values in the linear equation, which is Y = mx + b

8 0

3 years ago

Read 2 more answers

You roll a six sided die how likely is it that you roll a number greater than or equal to 1

Grace [21]

Answer:

6/6

Step-by-step explanation:

3 0

3 years ago