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marta [7]
4 years ago
6

The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation

of 5 points. About what percent of students have scored between 60 and 65 points?
Mathematics
2 answers:
8_murik_8 [283]4 years ago
7 0

Answer:

34%

Step-by-step explanation:

Using Empirical Rule (68 - 95 - 99.7 Rule), 68% of the data lies in between 1 standard deivation from the mean so since you are not doing 55 to 65 and instead 60 to 65, you divide 68 by 2 and you get 34%.

Please mark for Brainliest!! :D Thanks!!

For any questions or more information, please comment below and I'll respond as soon as possible.

Shalnov [3]4 years ago
6 0

Answer: The percent of students have scored between 60 and 65 points is 34.13%

Step-by-step explanation:

Given : The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation of 5 points.

i.e. \mu=60\ \ \ \sigma=5

Let x denotes the points obtained by students of a class in a test .

Now , the probability that the students have scored between 60 and 65 points :-

P(60

=34.13\%

Hence, the percent of students have scored between 60 and 65 points is 34.13%.

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Choice A

Step-by-step explanation:

All the sides appear to be equal which is a characteristic of squares.

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Finally, the sides appear to be parallel to each other.

4 0
3 years ago
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2 years ago
Surface Area of the pyramid
hichkok12 [17]

Answer:

C

Step-by-step explanation:

the total surface area of such a pyramid is the sum of 5 areas :

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now, we know the baseline of the 4 triangles, but what is their height (at least we know, all 4 have the same height, as the pyramid is totally regular) ?

the height of the side triangles is the slant height of the pyramid (the distance from the middle of a sideline to the top of the pyramid).

we get this by imagining a right-angled triangle inside the pyramid :

one leg is the inner height of the pyramid.

the second leg is the connection on the bottom square from the base of the inner height to the middle point of a sideline). this is half the length of a sideline.

and the baseline (Hypotenuse) is the slant height of the pyramid.

we can use Pythagoras

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64 + 128.996124... = 192.996124... in² ≈ 193.00 in²

8 0
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Answer:

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