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Leni [432]
2 years ago
8

Braniliest

Mathematics
1 answer:
Paul [167]2 years ago
3 0

Answer:

D. 28

Step-by-step explanation:

This answer is it because 28 is greater than 25.

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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)
Pie

Answer:

The ratio of AC/CB=1/3

Step-by-step explanation:

We use the section formula:

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n})

This is supposed to be equal to: (0,2).

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)

We can equate, corresponding coordinates to find m and n.

\frac{4.5m - 1.5n}{m + n}  = 0

This implies that:

4.5m - 1.5n = 0

4.5m  = 1.5n

\frac{m}{n}  =  \frac{1.5}{4.5}

\frac{m}{n}  =  \frac{1}{3}

Therefore the ratio is m:n=1:3

4 0
3 years ago
Which integer represents a golf score of 4 over par?
fgiga [73]
Omg ur learning about integers, I'm learning about integers too, what grade are you in?
7 0
3 years ago
State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
5 • 3n algebra functions
jok3333 [9.3K]
5 x 3n = 15n

^ This is your answer to your question ^
6 0
3 years ago
use a compass to draw a circle and cut it out fold the circle three times as shown to get equal wedges unfold and shade one half
astra-53 [7]

Answer:

subject?

Step-by-step explanation:

5 0
3 years ago
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