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2 years ago

Braniliest

Mathematics

1 answer:

Paul [167]2 years ago

3 0

Answer:

D. 28

Step-by-step explanation:

This answer is it because 28 is greater than 25.

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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)

Pie

Answer:

The ratio of AC/CB=1/3

Step-by-step explanation:

We use the section formula:

$(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})$

We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

$(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n})$

This is supposed to be equal to: (0,2).

$(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)$

We can equate, corresponding coordinates to find m and n.

$\frac{4.5m - 1.5n}{m + n} = 0$

This implies that:

$4.5m - 1.5n = 0$

$4.5m = 1.5n$

$\frac{m}{n} = \frac{1.5}{4.5}$

$\frac{m}{n} = \frac{1}{3}$

Therefore the ratio is m:n=1:3

4 0

3 years ago

Which integer represents a golf score of 4 over par?

fgiga [73]

Omg ur learning about integers, I'm learning about integers too, what grade are you in?

7 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

5 • 3n algebra functions

jok3333 [9.3K]

5 x 3n = 15n

^ This is your answer to your question ^

6 0

3 years ago

use a compass to draw a circle and cut it out fold the circle three times as shown to get equal wedges unfold and shade one half

astra-53 [7]

Answer:

subject?

Step-by-step explanation:

5 0

3 years ago