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dem82 [27]
4 years ago
8

Pls help Me with this one

Mathematics
1 answer:
Viktor [21]4 years ago
6 0
16÷4=4 12÷4=8 8÷4= 4
16-4=12 12-4=8 8-4=4
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Hello can someone help with this math sheet, the questions are kind of hard to me and i dont get it [please help]!! 45 points!!
NNADVOKAT [17]

Answer:

649*646/

Step-by-step explanation:

hope its help for you thank you

7 0
3 years ago
I need helpppppppppppppp
Fynjy0 [20]
We can see if the first two options are correct. The first one is eliminated because when x is 2, y is 5 and there is not a different of 5, only 3. This could make you think that the second option is the right answer, but when x is 1, y is 6 and the difference is 5, not 3. 
The third choice we could try out.
6=-(1)+7
5=-(2)+7
4=-(3)+7
3=-(4)+7
Let's look at the graph also. The coordinates are on the line.
So the third option, y=-x+7

5 0
3 years ago
Which of the following is not a valid probability?
Marta_Voda [28]

Answer:

D

Step-by-step explanation:

Probability cannot be greater than 1 so the answer is D.

8 0
3 years ago
Greg has 60 building blocks. His sister gives him 17 more blocks. He uses 38 blocks to make a tower. How many blacks are not use
kykrilka [37]

Answer:

Greg has 39 remaining blocks that are not used in the tower.

Step-by-step explanation:

According to the question, Greg started with 60 building blocks.  However, his sister gives him 17 more blocks.  The key word 'more' means we need to add these blocks to the original 60:  60 + 17 = 77.  Greg then decides to use 38 blocks to make a tower.  Since he is using these blocks from his total of 77, we need to subtract this number to see how many he has left:  77 - 38 = 39.  This means that Greg has 39 blocks left that were not used to build his tower.  

8 0
3 years ago
X^4 + 25 = 26x^2<br><br>please answer quick. I'll give brainliest rothe first person​
Shalnov [3]

{ \leadsto{ \sf{ \green{ {x}^{4}  + 25 = 26 {x}^{2} }}}} \\  \\ { \leadsto{ \sf{ \green{ {x}^{4}  - 26 {x}^{2}  + 25 = 0}}}} \\  \\ { \sf{ \underline{ \blue{let  \:  \: {x}^{2} \:  be \: equal \: to \: a}}}}

{ \leadsto { \green{ \sf{ {a}^{2}  - 26a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - (a + 25a) + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - a - 25a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{a(a - 1) - 25(a - 1) = 0}}}}

{ \leadsto{ \sf{ \green{(a - 1)(a - 25) = 0}}}} \\  \\ { \sf{ substituting \: value \: of \: a}} \\  \\ { \rightarrow{ \sf{ \blue{( {x}^{2}  - 1)( {x}^{2}  - 25) = 0}}}} \\  \\ { \sf {{x}^{2}  = 1}}  \\ { \sf{ \underline{x = \: ±  \: 1}}} \\  \\  \\ { \sf {x}^{2}  = 25}  \\ { \sf{ \underline{x =  \: ± \: 5}}}

7 0
3 years ago
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