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Lemur [1.5K]
3 years ago
11

PLS HELPPPPPPPPPP ......

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer: I don’t know

Step-by-step explanation:

Jsjsjdjdjdjdj

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I can't write the symbol, but it would be X<30 and the <would have a horizontal line under it so that it would mean x is less than or equal to 30
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The graph of y ≤-2x+4 is shown. Which set contains only points that satisfy the inequality?
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The answer is A
(0,0) (1,2) (3,-3)
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2 years ago
Right triangles and trigonometry help!
Maslowich

Step-by-step explanation:

sin \: 45 \degree =  \frac{39}{z}  \\  \\  \therefore \:  \frac{1}{ \sqrt{2} }  =  \frac{39}{z}   \\  \\  \therefore \: z = 39 \sqrt{2}  \\ let \: p \: be \: the \: perpendicular \:  \\  \\\therefore \: tan \: 45 \degree =  \frac{39}{p}  \\  \\ \therefore \:1 = \frac{39}{p}  \\  \\ \therefore \:p = 39 \\  \\ sin \: 60 \degree =  \frac{39}{x}   \\  \\ \therefore \:  \frac{ \sqrt{3} }{2} =  \frac{39}{x}  \\  \\ \therefore \: x =  \frac{78}{ \sqrt{3} }  \\  \\ \therefore \: x =  \frac{78 \sqrt{3} }{ 3 }  \\  \\ \therefore \: x =  26 \sqrt{3} \\\\tan\: 60 \degree =  \frac{39}{y}   \\  \\ \therefore \:  \sqrt{3}  =  \frac{39}{y}  \\  \\ \therefore \: y =  \frac{39}{ \sqrt{3} }  \\  \\ \therefore \: y=  \frac{39 \sqrt{3} }{ 3 }  \\  \\ \therefore \: y =  13 \sqrt{3} \\

5 0
3 years ago
If the area of the circle below is 18 ft2, what is the area of the shaded sector?
Arlecino [84]
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3 years ago
NO SCAM PLEASEEEE
damaskus [11]
The answer is 11/36

2/12 chance of rolling fours

because there are 2 sides containing a four on both dice combined and 12 sides in total.

Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.

I personally like to imagine a box like this:
_ _ _ _ _ _
|
|
|
|
|
|

If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.

1/6 * 1/6 = 1/36 chance to roll double of ones

And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:

1/36 * 5 = 5/36

So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:

5/36 + 2/12 =

5/36 + 6/36 =

11/36
5 0
3 years ago
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