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3 years ago

Pls help :))))))))) uhhhhhhhhh

Mathematics

1 answer:

Deffense [45]3 years ago

8 0

The answers are 3 and -13

You need to plug 3 and -5 into x

By doing this, you get :

12 - 3^2 and

12 - (-5)^2

those expressions equal

12 - 9

12 - 25

So you get

-13

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The height (in inches) of adult men in the United States is believed to be Normally distributed with mean μ . The average height

Jlenok [28]

Answer: a. 69.72 ± 1.37

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean height (in inches) of adult men in the United States.

Number of sample, n = 25

Mean, u = 69.72 inches

Standard deviation, s = 4.15

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z × standard deviation/√n

It becomes

69.72 ± 1.645 × 4.15/√25

= 69.72 ± 1.645 × 0.83

= 69.72 ± 1.37

The lower end of the confidence interval is 69.72 - 1.37 = 68.35

The upper end of the confidence interval is 69.72 + 1.37 = 71.09

5 0

3 years ago

Plz help this is due tomarrow

Olin [163]

The independent is a sentence that can stand alone a dependent isn't

3 0

3 years ago

Read 2 more answers

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$

8 0

3 years ago

Help please.!!

Dafna11 [192]

Answer: The answer is (y^2) to the power of -0.5

Step-by-step explanation:

8 0

3 years ago

What is the percent decrease from 60 to 39?

IrinaK [193]

X - the percent decrease

$60-60x=39 \ \ \ |-60 \\
-60x=-21 \ \ \ |\div (-60) \\
x=\frac{-21}{-60} \\ \Downarrow \\ x=\frac{-21}{-60}=\frac{-21 \div (-3)}{-60 \div (-3)}=\frac{7}{20}=\frac{7 \times 5}{20 \times 5}=\frac{35}{100}=35\%$

It's a 35% decrease.

7 0

3 years ago

Read 2 more answers

Pls help :))))))))) uhhhhhhhhh​

Pls help :))))))))) uhhhhhhhhh