Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer: 900 Km.
Step-by-step explanation: ...
'Pi' ( π ) is the ratio of the circumference of a circle to its diameter.
The exact value of 'pi' can't be completely written with numbers, so whenever
we use 'pi', we always use an approximation.
Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level : 
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test :
[By p-value table]
Since, 0.1031 > 0.05
i.e. p-value > 
So, we fail to reject the null hypothesis. [When p<
then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.