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omeli [17]
3 years ago
8

A square has side length 3 units. What is the length of the diagonal?

Mathematics
1 answer:
ella [17]3 years ago
4 0

9514 1404 393

Answer:

  C. 3√2 units

Step-by-step explanation:

The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.

__

If you like, you can see this using the Pythagorean theorem.

  d² = s² + s² . . . . . where d is the diagonal, and s is the side

  d² = 2s²

  d = √(2s²) = s√2

For s=3, ...

  d = 3√2

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Answer:

3.8

Step-by-step explanation:

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In a three hour TV broadcast the commercials show 29% of the time. How many minutes of commercials are shown each hour? Round to
Sedaia [141]

Answer:

There are 17.4 minutes of commercials are shown each hour.

Step-by-step explanation:

An hour has 60 minutes.

So in 3 hours, there are 3*60 = 180 minutes.

The commercials show 29% of the time.

So we have 0.29*180 = 52.2 minutes, in total, of commercial.

Per hour, we have 52.2/3 = 17.4 minutes of commercial.

7 0
3 years ago
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Answer:

y >   \boxed{\cfrac{42}{5} }

Step-by-step explanation:

Given inequality:

\cfrac{y}{3} > 7 - \cfrac{y}{2}

To solve for <em>y.</em>

Solution:

Rewrite the inequality as,

  • \displaystyle \frac{1y}{3}  >   \frac{ - 1}{2} y + 7

Adding 1/2y to both sides,

  • \cfrac{1}{3} y +  \cfrac{ 1 }{2} y >  \cfrac{ - 1}{2}y  + 7 +  \cfrac{1}{2} y

  • \cfrac{5}{6} y > 7

Multiplying both sides by 6/5:

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  • y >   \boxed{\cfrac{42}{5} }

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7 0
2 years ago
(PLEASE HELP) A contractor has 10 lots for sale to build on. 4 lots are greater than two acres. 6 lots are less than two acres.
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Probability that the first lot sold will be less than two acres = number of lots less than two acres / total number of lots = 6/10 = 3/5
 
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Required probability = 3/5 x 5/9 = 15/45 = 1/3
8 0
3 years ago
At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how m
jok3333 [9.3K]

Answer:

52 young calves

Step-by-step explanation:

At a dairy farm the ratio of adult milking cows to young calves was 9:2. If there were 234 adult milking cows at the farm, how many young calves were there?

The ration is given as:

adult milking cows to young calves

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= 234 : x

= 9/2 = 234/x

x = Number of young calves

Cross Multiply

9 × x = 2 × 234

= x = 2 × 234/9

x = 468/9

x = 52

Hence, the number of young calves on the farm is 52.

7 0
3 years ago
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