Please help!
1 answer:
You might be interested in
Answer:
x = - , x = 3
Step-by-step explanation:
To find the zeros let p(x) = 0 , that is
2x² - 3x - 9 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 9 = - 18 and sum = - 3
The factors are - 6 and + 3
Use these factors to split the x- term
2x² - 6x + 3x - 9 = 0 ( factor the first/second and third/fourth terms)
2x(x - 3) + 3(x - 3) = 0 ← factor out (x - 3) from each term
(x - 3)(2x + 3) = 0
Equate each factor to zero and solve for x
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
x - 3 = 0 ⇒ x = 3
<u>Answer: </u>
The vertex of the function is (h,k) = (3 , -1)
<u>Solution: </u>
The vertex form of quadratic equation is generally given as,
Where h,k is the vertex of the parabola.
From question, given that .
we have to find the vertex of the function.
Let us first convert the given quadratic equation to vertex form (eqn 1)
By adding “9” on both sides of equation, we get
By using the identity ,the right hand side of above equation becomes,
Now,the equation is of the vertex form.
By comparing with
we get the values of (h,k)
a = 1; h = 3; k = -1
hence the vertex of the function is (h,k) = (3 , -1)