Answer:
Step-by-step explanation:
^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]](https://tex.z-dn.net/?f=y%27%3D%5B%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2-4%29%5E5%5D%283x%2B4%29%5E4%2B%28x%5E2-4%29%5E5%5B%5Cfrac%7Bd%7D%7Bdx%7D%283x%2B4%29%5E4%5D)
103.468
Since 4 rounds down:
103
Hope this helps!
F = kq2 / r2
q = ne
F = k(ne)2 / r2
n = âš(r2F / ke2) = (r/e) âš(F/k)
k = 9 x 109 Nm2/C2
e = 1.6 x 10-19 C
n = [(4.2 x 10-10) / (1.6 x 10-19)] âš[(5.2 x 10-9) / (9 x 109)] ≅ 1.995 ≅ 2
x = total amount of students in 8th Grade.
we know only one-thrid of the class went, so (1/3)x or x/3 went.
we also know 5 coaches went too, and that the total amount of that is 41.
now, to verify, well, what do you get for (108/3) + 5?
Answer:
29.74 degrees.
Step-by-step explanation:
Tan(theta) = opposite / adjcent.
opposite = 8
adjacent = 14
Tan(theta) = 8/14
Tan(theta) = 0.5714
theta = tan^-1(0.5714)
theta = 29.74 degrees
