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Brilliant_brown [7]
3 years ago
8

alex sells cars at keith palmer ford. he earns $400 a week plus $150 percar he sells. if he earned $150 last week , how many car

s did he sell?
Mathematics
2 answers:
viktelen [127]3 years ago
5 0
He gets $400 a week plus 150 for each car so he sold only 1 car
Igoryamba3 years ago
3 0

Alex would have sold one car

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Answer and question is in the pictures.
bogdanovich [222]

Answer:

< - 52, 48 > and 70.77

Step-by-step explanation:

2v - 6u

= 2<- 11, 3 > - 6 < 5, - 7 >

= < - 22, 6 > - < 30, - 42 >

= < - 52, 48 >

| 2v - 6u | = \sqrt{(-52)^2+(48)^2} = \sqrt{5008} = 70.77


7 0
3 years ago
Evaluate the expression 6•14-(9+8)2
lora16 [44]

Answer:

50

Step-by-step explanation:

First things first, use PEMDAS.

Parenthesis is first.

(9+8) is in parenthesis. 9+8 is obviously 17.

The equation now looks like this:

6 x 14 - 17 x 2

There is no exponents, but there is multiplication. 6 x 14 is 84 and 17 x 2 is 34. They both are multiplication equations.

The equation now looks like this:

84 - 34

84-34 is 50. 50 is your answer.

8 0
3 years ago
In Debi's Girl Scout troop.
bazaltina [42]
I hate Brainly ........................
3 0
3 years ago
help me please can someone please help i beg you. i have to say why this is wrong and solve this correctly. i beg you please
e-lub [12.9K]

Answer:

The person solving the problem first subtracted 6 from 15. Since the cube root is next to the six, the problem should be read as 15-6(\sqrt[3]{\frac{-1000}{27} } ) rather than (15-6)(\sqrt[3]{\frac{-1000}{27} } ).

  • To solve it correctly, first find the cube root of -1000/27: <u>-10/3</u>
  • Next, multiply by 6: -20
  • Finally, subtract from 15: 35

please lmk if anything is wrong with my answer, hope this helps :)

5 0
3 years ago
Radium-228 has a half-life of 5.75 years. What is the decay rate for radium-228?
artcher [175]

Decay rate for Radium-228 is 0.01205

Step-by-step explanation:

The half life of radium-228 is 5.75 years. We need to find the decay rate for radium.

The formula used is:

ln\frac{N_o}{N_t}=-\lambda t

Where N₀ = amount of radioactive particles at time = 0

N_t = amount of radioactive particles are time (t)

λ = rate of decay constant

t = time

We are given half life so, \frac{N_o}{N_t}=0.5

t= 5.75 years

We need to find λ

Putting values in formula and solving:

ln\frac{N_o}{N_t}=-\lambda t

ln(0.5)=-\lambda *5.75\\-\lambda=\frac{ln(0.5)}{5.75}\\-\lambda=\frac{-0.69}{5.75}\\-\lambda=-0.1205\\\lambda=0.1205

So, Decay rate for Radium-228 is 0.01205.

Keywords: Decay Rate

Learn more about Decay Rate at:

  • brainly.com/question/4361464
  • brainly.com/question/8224301

#learnwithBrainly

3 0
3 years ago
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