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Levart [38]
3 years ago
8

A fan starts from 5 rad/s and speeds up at a constant angular acceleration of 25 rad/s^2 for 5.0 seconds. What is the final angu

lar velocity of the fan (in radians/second)​
Physics
1 answer:
netineya [11]3 years ago
6 0

<em>ω</em> = <em>ω</em>₀ + <em>α t</em>

where

<em>ω</em> = final angular velocity

<em>ω</em>₀ = initial angular velocity = 5 rad/s

<em>α </em>= angular acceleration = 25 rad/s²

<em>t</em> = time = 5.0 s

Solve for <em>ω</em> :

<em>ω</em> = 5 rad/s + (25 rad/s²) (5.0 s) = 130 rad/s

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A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
miv72 [106K]
  • Current=2.5A=I
  • Inductance=B=5H

We know

\boxed{\sf Magnetic\:flux=\O=BA}

\\ \qquad\quad\sf{:}\dashrightarrow \O=5(2.5)

\\ \qquad\quad\sf{:}\dashrightarrow \O=12.5Wb

3 0
3 years ago
Help m-e-e people -_-!​
xxTIMURxx [149]

Answer:

the answer is

Explanation:For equilibrium

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mg=T

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Y=

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​

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0.031

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12.4π/π(

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6 0
3 years ago
A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A
vesna_86 [32]

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

6 0
3 years ago
Calculate the volume of a 5-g sample of pure gold
Bond [772]
  • Answer:

<em>≈ 0.26 cm³</em>

  • Explanation:

<em>Hi there !</em>

<em>Gold is a metal with a very high density.</em>

<em>The density of gold is higher than that of lead.</em>

<em>Density(gold) = 19300 kg/m³ = 19.3 g/cm³</em>

<em />

<em>19.3 g ............ 1 cm³</em>

<em>5 g ..................x cm³</em>

<em>x = 5g×1cm³/19.3g = 0.2590 cm³ ≈ 0.26 cm³</em>

<em>Good luck ! </em>

5 0
4 years ago
What is the differnce between kinetic and potential energy
Tems11 [23]
I think the answer should be that, Kinetic energy is contained in a moving object, while potential energy exists in a stored form.
5 0
4 years ago
Read 2 more answers
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