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hoa [83]
3 years ago
11

Describe the image with a object distance of 65cm and a focal length of 20cm

Physics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

Imag distance = 28.9 cm

Explanation:

Given that,

Object distance, u = -65 cm

The focal length of the convex les, f = +20 cm

We need to find the image distance. The lens formula gives the relation between focal length, object distance and image distance is given by :

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{20}+\dfrac{1}{-65}\\\\v=28.9\ cm

So, the image distance is 28.9 cm

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How would you obtain a mean value for the specific heat<br> capacity of a material?
lidiya [134]
The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
8 0
3 years ago
State three ways in which a machines are useful to us.
olga2289 [7]
1: a machine makes our work easier

2: a machine can help us find important information

3: a machine can help us transport from a place to another
3 0
3 years ago
Standard twist-on wire connectors are not suitable for terminating or splicing aluminum or copper-clad aluminum conductors.
Rainbow [258]

Answer:

True.

Explanation:

Twist-on wire connectors are a sort of electrical conduit used only to fasten two or more small tension (or extra-low tension) electrical conductors.They are also called wire nuts, wire connectors or cone connectors( because of their conical shape). They are not suitable for for terminating or splicing aluminum or copper-clad aluminum conductors.

Hence the above statement is true.

4 0
3 years ago
A gold bar has a density of 19.3 g/mL. If the gold bar has a mass of 6.3 grams, what is the volume?
Natali [406]

Answer:

The correct answer is "0.32 mL".

Explanation:

The given values are:

Density of gold bar,

d = 19.3 g/mL

Mass of gold bar,

m = 6.3 grams

Now,

The volume will be:

⇒  Density = \frac{Mass}{Volume}

or,

⇒  Volume=\frac{Mass}{Density}

On substituting the values, we get

⇒               =\frac{6.3 \ g}{19.3 \ g/mL}

⇒               =0.32 \ mL

7 0
3 years ago
A bullet of mass 0.0021 kg initially moving at 497 m/s embeds itself in a large fixed piece of wood and travels 0.65 m before co
alina1380 [7]

Answer:

The force exerted by the wood on the bullet is 399.01 N

Explanation:

Given;

mass of bullet, m = 0.0021 kg

initial velocity of the bullet, u = 497 m/s

final velocity of the bullet, v = 0

distance traveled by the bullet, S = 0.65 m

Determine the acceleration of the bullet which is the deceleration.

Apply kinematic equation;

V² = U² + 2aS

0 = 497² - (2 x 0.65)a

0 = 247009 - 1.3a

1.3a = 247009

a = 247009 / 1.3

a = 190006.92 m/s²

Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;

F = ma

F = 0.0021 x 190006.92

F = 399.01 N

Therefore, the force exerted by the wood on the bullet is 399.01 N

6 0
3 years ago
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