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Ymorist [56]
3 years ago
11

Helpppppppppppppy pls

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

Step-by-step explanation:

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Solve for x. 3x - 1 = 27 x = 10 x = 28/3 x = 26/3
frutty [35]

Answer:

x = 28/3

Step-by-step explanation:

3x - 1 = 27

Add 1 to each side

3x - 1+1 = 27+1

3x = 28

Divide by 3

3x/3 = 28/3

x = 28/3

6 0
2 years ago
which equation is the quadratic variation equation for the relatonship? the variable y varies directly with x^2 and y=36 when x=
svetoff [14.1K]

For this case we have a direct variation of the form:

y = kx ^ 2

Where,

  • <em>k: proportionality constant </em>

We must find the value of k.

For this, we use the following data:

y = 36\\x = 3

Therefore, replacing values we have:

36 = k (3) ^ 2

Rewriting:

36 = 9k

Clearing the value of k we have:

k = \frac {36} {9}\\k = 4

Therefore, the direct variation equation is given by:

y = 4x ^ 2

Answer:

The quadratic variation equation for the relatonship is:

y = 4x ^ 2

8 0
2 years ago
The total surface area of a cuboid is 600cm ^2 find LSA
Alona [7]

Answer:

Hope this help uh

Please make me brilliant

8 0
2 years ago
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
3 years ago
at your local video store, you can rent movies for $2 per movie plus a $10 membership fee for the year. you have $20 to spend on
exis [7]
2x+10 is less than or equal to 20
the domain is 0, 1, 2, 3, 4, 5.
5 0
3 years ago
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