Rotate the following point (- 5, 7) with a 90 degree CCW rotation
1 answer:
Given:
The point is (-5,7).
To find:
The image of the given point after 90 degrees counter clockwise rotation.
Solution:
If a point rotated 90 degrees counter clockwise, then
Let the given point is P(-5,7). Using the above rule, we get
Therefore, the image of the given point after 90 degrees counter clockwise rotation is (-7,-5).
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sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule,
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option