Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Use slander and search textbook up it will show up with answers
Answer:
There is no question.
Step-by-step explanation:
Answer: 5
Step-by-step explanation:
change in y/change in x
y2-y1/x2-x1
-1--5/0-2
-1+5/-2
4/-2
-2
slope is -2
now take one ordered pair and plug it into the equation (for this example i will use the SECOND ordered pair
y = -2x +b
-1 = -2(0)+b
-1 = b
the equation is
<h2>
y = -2x - 1</h2>
