If the amount of time taken to go said distance is x and the amount of time taken to go back said distance is y, then the amount of miles total is 7x+3y due to that for every hour, she adds 7 miles when going there and 3 miles for walking back. In addition, since the total amount of time is 4 hours, x+y=4 as the total time spent as well as 7x=3y due to that they're the same distance.
x+y=4
7x=3y
Dividing the second equation by 7, we get x=3y/7. Plugging that into the first equation, we get 3y/7+y=4=10y/7 (since y=7y/7). Multiplying both sides by 7 and then dividing both by 10, we get 28/10=2.8=y in hours. Since 0.1 hours is 60/10=6 minutes, and 0.8/0.1=8, 6*8=48 minutes=0.8 hours, meaning that she should plan to spend 2 hours and 48 minutes walking back
Answer:
A.( 3m+28)/4
Step-by-step explanation:
So basically since it is addition we just add 9 to -2 to get 7. So then the equation becomes (3m/4)+7. Then we will multiply 7 by 4 to get common denominator so it will be (3m+(7*4))/4 which is (3m+28)/4.
Answer:
y > -1/4x + 4
Step-by-step explanation:
First find the equation of the line itself, which is y = -1/4x + 4, then determine if graph shades above the line or below the line. If it shades above which is true in this case, it will be greater than. If it shades below which does not occur in this case, it will be less than. Because the line is dashed and not solid, it will just be greater than or less than.
Therefore y = -1/4x + 4 → y > -1/4x + 4 [Shades above the line, line is dashed].
Answer:
(6, 3)
Step-by-step explanation:
Since, the triangle PQR is rotated 360° around the origin so, Q' will coincide with Q, and in this way their coordinates would be same.
Therefore, Q' (6, 3)
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
