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densk [106]
3 years ago
6

A(n) _____ transition shows that one event happened before another. Some examples of this type of transition are "so," "therefor

e," "hence," and "as a result. "A.contras tB.cause-and-effect C.order-of-importance
D.summary
Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0
B. Cause and effect should be the answer
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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
The base of a cube is 1/4 ft squared. Whats the volume of the cube? also can you explain your answer so i can answer other quest
MrMuchimi
It would be 1/64 I hope this helps with your question.
8 0
3 years ago
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A veterinarian weighs three cats. The American Shorthair weighs 13.65 pounds. The Persian weighs 13.07 pounds, and the Maine Coo
Alex_Xolod [135]

Answer:

Persian, Maine Coon, American Shorthair

13.07, 13.6, 13.65

Step-by-step explanation:

I hope this helped!

7 0
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How do you find the value of X? Isosceles and Equilateral Traingle
Svetradugi [14.3K]
Did they give values for the letters??
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Solve for r. p = 4r 3t
notsponge [240]
P = 4r + 3t
4r = p - 3t
r = (p - 3t)/4
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