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2 years ago

43 - 12y = 8 41 + 12y = 56

Mathematics

1 answer:

Anna71 [15]2 years ago

7 0

Answer:

no solution

Step-by-step explanation:

+12y and -12y cancel each other out.

we are left with 43+41=8+56

84 doesn't equal 64

so NO SOLUTION

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Step-by-step explanation:

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What property can I use for this question: 3x57

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<h2>====LEARN WITH REY====</h2>

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Step-by-step explanation:

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3 years ago

Find the hcf of 120 and 150

Alexeev081 [22]

Answer: GCF = 30 for the values 120, 150

Step-by-step explanation:

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

The factors of 150 are: 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Then the greatest common factor is 30.

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2 years ago

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Expand log_1/2(3x^2/2) using the properties and rules for logarithms.<br><br><br> Please help.

Naily [24]

Answer:

$\frac{0.1761+2\log(x)}{-0.3010}$

Step-by-step explanation:

Data provided:

$\log_{1/2}(\frac{3x^2}{2})$

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) $\log(\frac{A}{B})$ = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3x^2)$ - $\log_{1/2}(2)$

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+\log_{\frac{1}{2}}(x^2)$ - $\log_{1/2}(2)$

using property 3

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+2\log_{\frac{1}{2}}(x)$ - $\log_{1/2}(2)$

also,

$\log_a(x)=\frac{\log(x)}{\log(a)}$

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}$

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.4771+2\log(x)-0.3010}{0-0.3010}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.1761+2\log(x)}{-0.3010}$

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3 years ago

Read 2 more answers