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3 years ago

9. If ground beef costs $4.98 for 3 pounds, then what is the unit rate (cost per

Mathematics

1 answer:

Drupady [299]3 years ago

4 0

Answer:

1.66 pounds

Step-by-step explanation:

4.98 dollars divided by 3 pounds

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Is 49 a perfect square

Sholpan [36]

Yes, it is also a square number

8 0

3 years ago

Read 2 more answers

A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p

bagirrra123 [75]

Given,

CP of cosmetics = Rs 360 per dozen

SP of a pair of cosmetics = Rs 80

To find,

The gain percent

Solution,

1 dozen = 12 items

CP of 1 cosmetic = 360/12 = Rs 30

SP of 1 cosmetic = 80/2 = Rs 40

Profit = SP-CP

= Rs 40 - Rs 30

= Rs 10

Profit percentage is given by :

$\%=\dfrac{profit}{CP}\times 100\\\\=\dfrac{10}{30}\times 100\\\\=33.34\%$

So, the profit percentage is 33.34%.

5 0

2 years ago

A student solved for the radius of a circle with a circumference of 12π

padilas [110]

Answer:

Step 4 is incorrect he did not divide correctly from step3 to step 4

Step-by-step explanation:

The circumference of a circle is

C = 2 * pi *r

We know the circumference is 12 pi

12pi = 2 pi *r

Divide each side by 2 pi

12 pi/2pi = 2pi r/ 2pi

6 = r

From step 3 The student did not cancel the pi in the top and the bottom on the right hand side to isolate r

In step 4 he got 6 =pi r instead of pi

3 0

3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

11Alexandr11 [23.1K]

<h3>Answer: B) Only the first equation is an identity</h3>

========================

I'm using x in place of theta. For each equation, I'm only altering the left hand side.

Part 1

cos(270+x) = sin(x)

cos(270)cos(x) - sin(270)sin(x) = sin(x)

0*cos(x) - (-1)*sin(x) = sin(x)

0 + sin(x) = sin(x)

sin(x) = sin(x) ... equation is true

Identity is confirmed

---------------------------------

Part 2

sin(270+x) = -sin(x)

sin(270)cos(x) + cos(270)sin(x) = -sin(x)

-1*cos(x) + 0*sin(x) = -sin(x)

-cos(x) = -sin(x)

We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.

7 0

2 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unknown

kiruha [24]

Answer:

The other endpoint is (-33, 17)

Step-by-step explanation:

The rule of the mid-point of a segment whose endpoints are

( $x_{1}$ , $y_{1}$ ) and ( $x_{2}$ , $y_{2}$ ) is

$(x_{M},y_{M}) = (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

In our question

∵ The coordinates of the endpoints of a segment are (-15, 13) and (x, y)

∴ $x_{1}$ = -15 and $x_{2}$ = x

∴ $y_{1}$ = 13 and $y_{2}$ = y

∵ The coordinates of the mid-point of this segment are (-24, 15)

∴ $x_{M}$ = -24 and $y_{M}$ = 15

→ Use the rule of the mid-point to find x and y

∵ $-24=\frac{-15+x}{2}$

→ Multiply both sides by 2

∴ -48 = -15 + x

→ Add 15 to both sides

∴ -33 = x

∵ $15=\frac{13+y}{2}$

→ Multiply both sides by 2

∴ 30 = 13 + y

→ Subtract 13 from both sides

∴ 17 = y

∴ The other endpoint is (-33, 17)

5 0

3 years ago