2/9 right???? because if you spin it you have a 1/9 chance for each number or would the answer be 2/81
The 3rd and 5th systems of equations are the answer.
Point A is at (3,-1), so all you do is input 3 for x and -1 for y into all the equations. For the systems to work, both equations must work with (3,-1).
Only the third and fifth boxes work.
The least number of quadratic system can have is Two real solutions or no real solutions.
Answer:
im sorry but i need points
Step-by-step explanation:
Answer:
23, 25, 27
Step-by-step explanation:
It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.
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<h3>setup</h3>
Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...
2(x -2) +3x = 67 +2(x +2)
<h3>solution</h3>
5x -4 = 2x +71 . . . . . simplify
3x = 75 . . . . . . . . add 4-2x
x = 25 . . . . . . . divide by 3
The three integers are 23, 25, 27.
