I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.
Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.
For the second question:
I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.
So, the answers are: A) and D).
Answer:
The answer to your question is SV = 32
Step-by-step explanation:
Data
T = mid point
ST = x + 4
TV = 2x - 8
SV = ?
Process
1.- If T is the mid point of SV, that means that the distance from ST to SV is the same.
ST = TV
2.- Substitution
x + 4 = 2x - 8
-Solve for x
x - 2x = -8 - 4
-Simplifying
-x = -12
-Result
x = 12
3.- Find the length of SV
SV = ST + TV
SV = x + 4 + 2x - 8
SV = 12 + 4 + 2(12) - 8
SV = 16 + 24 - 8
SV = 40 - 8
SV = 32
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
