Question

An observer 2.5 miles from the launch pad of a space shuttle measures the angle of elevation to the base of the shuttle to be 25◦ soon after lift-off. d Observer θ How high is the shuttle at that instant (assuming that the shuttle is still moving vertically)? Answer in units of miles.

Answer 1

Answer:

Height of shuttle at that instant  = 1.17 miles

Step-by-step explanation:

Refer the given figure.

C is the position of rocket and B is the position of observer.

Here we need to find AC, that is the height of shuttle at that instant.

Using trigonometric rules on ΔABC, we have

      $tan25=\frac{AC}{AB} \\\\tan25=\frac{AC}{2.5}\\\\AC=2.5\times tan25\\\\AC=1.17miles$

Height of shuttle at that instant = AC = 1.17 miles