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Ilia_Sergeevich [38]
3 years ago
5

Please tell me answers I am given you brainliest ​

Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0

Angle QPS=110°

x =180°-110° =70°(sum of Opposite Angles of cyclic quadrilateral=180°)

y = 180°- 70° =110° ( Angles on a straight line)

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Raymond normally has a snack consisting of ten 12-calorie crackers. How many 20-calorie cookies would he have to eat to consume
ss7ja [257]
<h3>Answer:  6</h3>

Work Shown:

He eats ten 12-calorie crackers, so that is 10*12 = 120 calories total

If x is the number of 20-calorie cookies, then the total number of calories here is 20x. We want this to be 120, so,

20x = 120

x = 120/20 .... divide both sides by 20

x = 6

He must eat six 20-calorie cookies to get 120 calories total

3 0
4 years ago
Read 2 more answers
What is the least common multiple (LCM) of 5 and 12?
geniusboy [140]

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4 0
3 years ago
6x-2 (x-5) = 46 what’s x
olga nikolaevna [1]

Answer:

x = 9

Step-by-step explanation:

6x - 2(x - 5) = 46 ← distribute parenthesis and simplify left side

6x - 2x + 10 = 46

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4 0
2 years ago
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Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
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Determine the measure of &lt;0<br><br> 20.21°<br> 0.005<br> 73.74°<br> 16.26°
fomenos

Answer:

16.26°

Step-by-step explanation:

1. tanΘ= 7/24

2.tan^-1(\frac{7}{24} ) =Θ

3. Θ = 16.26°

6 0
3 years ago
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