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kipiarov [429]
3 years ago
12

I need help with the bottom part I know the top parr

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
You used distributive property because when there’s parentheses in a equation you need to distribute the number outside of the parentheses
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Heather is going to graph y= -3x^2 +3. How is the parent graph transformed
Akimi4 [234]
Well compared to the parent function x^2, the graph of y=-3x^2+3 is flipped upside down (negative sign), steeper, and is up 3 units from the origin.
6 0
3 years ago
Chapter 8 Written Homework 1. A hypothesis test is conducted to test the claim that the proportion of people with dark hair at M
UNO [17]

Answer:

we reject  H₀

Step-by-step explanation:  Se annex

The test is one tail-test (greater than)

Using   α = 0,05   (critical value )  from z- table we get

z(c) = 1,64

And Test hypothesis is:

H₀         Null hypothesis           μ   =  μ₀

Hₐ       Alternate hypothesis   μ   >  μ₀

Which we need to compare with z(s) = 2,19  (from problem statement)

The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region

So base on our drawing we will reject  H₀

3 0
3 years ago
When measuring and recording vital signs, healthcare professionals sometimes have to convert units of measurement, especially wh
nataly862011 [7]

Answer:

116°F = 46.67 °C and 6 Pounds = 2721.55 grams

Step-by-step explanation:

The information given in the question is 1°F = -17.22°C

1 Kilogram = 1000 grams = 2.2 pounds

And we have to convert 116° F to degrees Celsius and Six pounds to grams.

1) We know (°F-32)×5/9 =°C

So by putting the value of °F as 116 ⇒ (116-32)×5÷9 = °C

⇒ °C = \frac{(84)(5)}{9}

⇒ °C = 46.67

2). ∵ 2.2 Pounds = 1000 grams

     ∴1 Pound = 1000/2.2 = 454.54 grams

    ∴ 6 pounds = 6× 454.54 grams

                        = 2721.55 grams

   

4 0
3 years ago
Can someone help me please
IrinaVladis [17]

hey what's up! the answer is c

7 0
2 years ago
Find a vector equation for the line through the point P = (-3,3, -5) and parallel to the vector V= (-2,-4, -4). Assume 1-(0) =-3
CaHeK987 [17]

Answer:

The vector equation of the line is

l(t)= "-3,3,-5" + t "-2,-4,-4", where t is a parameter.

4 0
3 years ago
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