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IrinaVladis [17]
3 years ago
15

Solve the equation for the specified variable. Y=AB-2, For A

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

b = 1

b = -1

a = 0

Step-by-step explanation:

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Step-by-step explanation:

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Apply the distributive property to factor out the greatest common factor. 30 + 42
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3 years ago
What is the value of y in the sequence below<br> 2, У, 18,-54, 162
Maslowich

Answer:

<em>y=-6</em>

Step-by-step explanation:

<em>Geometric Sequences</em>

Any given sequence is said to be geometric if each term a_n can be obtained as the previous term a_{n-1} by a constant value called the common ratio.

a_n=a_{n-1}.r

or equivalently

a_n=a_1.r^{n-1}

Looking closely at the sequence 2, y, 18,-54, 162 we can try to find out if it's a geometric sequence or not. We compute the possible common ratios

\displaystyle \frac{162}{-54},\ \frac{-54}{18} and we see they both result -3. If we use r=-3 and try to find the second term (y), then

y=2*(-3)=-6

Now we compute the third term: (-6)(-3)=18

Since we got the third term as given in the original sequence.

So y=-6

3 0
3 years ago
Find the 7th term 18,6,2…
Veseljchak [2.6K]

If we look at the series, one third of the current term gives the numerical value of the next term.

If we need to express it algebraically, we can write the following equation.

  • a_{n+1}=\frac{a_{n}}{3}

Therefore, our common multiplier can be found as follows. Because this sequence is a geometric sequence.

  • \frac{a_{n+1}}{a_{n}} =r=\frac{1}{3}

In geometric sequences, any term can be written in terms of the first term. Below is an example.

  • a_{n}=a_{1}.r^{n-1}

Since we know the numerical values of the first term and the common factor of the series, we can easily find the seventh term.

  • a_{7}=a_{1}.r^{7-1}
  • a_{7}=18.(\frac{1}{3} )^6
  • a_{7}=\frac{2}{81}

6 0
1 year ago
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