Suppose a toy rocket is launched vertically upward from the top of a building with an initial velocity of 128 feet per second. i
f air resistance is ignored, the rocket's h height after t seconds is given by the equation h = −16t2 +128t + 100. How long will the rocket's flight last? (to the nearest tenth of a second) A) 7.6 seconds B) 7.9 seconds C) 8.7 seconds D) 9.3 seconds
1 answer:
Answer:
Option C)
t = 8.7 s
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The projectile formula is
h(t) = a*t^2 + v*t + h0
Where,
v = initial vertical velocity of the rocket in feet per second
h0 = initial height of the rocket in feet
h(t) = −16t^2 +128t + 100
If we look at the graph, we can find the point in which the height becomes zero. The value for t at this point will represent the rocket's fight duration
For this problem,
t = 8.717 s
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