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iren [92.7K]
3 years ago
8

Suppose a toy rocket is launched vertically upward from the top of a building with an initial velocity of 128 feet per second. i

f air resistance is ignored, the rocket's h height after t seconds is given by the equation h = −16t2 +128t + 100. How long will the rocket's flight last? (to the nearest tenth of a second) A) 7.6 seconds B) 7.9 seconds C) 8.7 seconds D) 9.3 seconds

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

Option C)

t = 8.7 s

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The projectile formula is

h(t) = a*t^2 + v*t + h0

Where,

v = initial vertical velocity of the rocket in feet per second

h0 = initial height of the rocket in feet

h(t) = −16t^2 +128t + 100

If we look at the graph, we can find the point in which the height becomes zero. The value for t at this point will represent the rocket's fight duration

For this problem,

t = 8.717 s

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see the attached figure to better understand the problem

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8 0
4 years ago
Read 2 more answers
PLEASE HELP SKJSDLFSKDJF
charle [14.2K]

45 min is 3/4 of an hour, 3/4 0f 40 km/h=30 km

75km/h x 2hr=150km

=180km

Total time:3hr

180kh/3hr=60km/h

sorry if im wrong

6 0
3 years ago
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