Answer:
Expected number of hours before the the group exits the building = E[Number of hours] = 3.2 hours
Step-by-step explanation:
Expected value, E(X) is given as
E(X) = Σ xᵢpᵢ
xᵢ = each variable
pᵢ = probability of each variable
Let X represent the number of hours before exiting the building taking each door. Note that D = Door
D | X | P(X)
1 | 3.0 | 0.2
2 | 3.5 | 0.1
3 | 5.0 | 0.2
4 | 2.5 | 0.5
E(X) = (3×0.2) + (3.5×0.1) + (5×0.2) + (2.5×0.5) = 3.2 hours
Hope this Helps!!!
I think it’s 3 (900 cm2) sorry if it’s wrong.
False because you in comepare and coaiser
Answer:
7 < y
Step-by-step explanation:
The relation you're interested in is ...
(4.5 -2y)/5 < (2 -3y)/10
9 -4y < 2 -3y . . . . . . . . . multiply by 10
7 < y . . . . . . . . . . . . . . . . add 4y-2
The value of the first fraction will be less than that of the second fraction for values of y greater than 7.
It is 25.2982212813 hope you have a good day
