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Yuri [45]
2 years ago
11

(06.01)The probability that an event will occur is 95%. Which of these best describes the likelihood of the event occurring? Lik

ely Certain Unlikely Impossible
Mathematics
2 answers:
-Dominant- [34]2 years ago
8 0

Answer:

likely           took the flvs test

Step-by-step explanation:

Elan Coil [88]2 years ago
3 0

Answer:

Likely

Step-by-step explanation:

The probability of occurrence of a certain event Given as 95% has a high probability figure and hence such event is LIKELY to occur. We cannot class this probability percentage as certain because, an event which is certain to occur who'll have a probability percentage of 100% or a value of 1. Therefore, a probability percentage of 95% occurrence still has 5% Chace of not happening, hence it is only very likely to occur. Hence, the phrase which best describes the probability of an event with 95% probability happening is LIKELY.

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Step-by-step explanation:

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3 years ago
(x*y=1210)=(-55=x+y)​
Romashka [77]
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I need help !!!!!!!!!!!!!
hoa [83]

Answer:

see below

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8 0
3 years ago
Please answer ASAP
labwork [276]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

A 12 cm cone with a dome on top of it that has an 8 cm diameter

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{Volume\:of\:the\:figure = 334.93\:cm^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

6 0
3 years ago
×/2=y/3; y/4=z/4 và x+2y-z=10
Nataly [62]

Answer:

try mo kayng magsolve wag puro brainly

4 0
3 years ago
Read 2 more answers
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