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aleksley [76]
2 years ago
11

Activity Give the exponential model for the following situation​

Mathematics
1 answer:
Otrada [13]2 years ago
6 0

Answer:

Suppose that a couple invested $50,000 in an account when their child was born, to prepare for the child's college education. If the average interest rate is 4.4% compounded annually, ( A ) Give an exponential model for the situation, and ( B ) Will the money be doubled by the time the child turns 18 years old?

( A ) First picture signifies the growth of money per year.

( B ) Yes, the money will be doubled as it's maturity would be $108,537.29.

a = p(1 + \frac{r}{n} ) {}^{nt}a=p(1+

n

r

)

nt

a = 50.000.00(1 + \frac{0.044}{1} ) {}^{(1)(18)}a=50.000.00(1+

1

0.044

)

(1)(18)

a = 50.000.00(1 + 0.044) {}^{(1)(18)}a=50.000.00(1+0.044)

(1)(18)

a = 50.000.00(1.044) {}^{(18)}a=50.000.00(1.044)

(18)

50,000.00 ( 2.17074583287910578440507440 it did not round off as the exact decimal is needed.

a = 108.537.29a=108.537.29

Step-by-step explanation:

Hope This Help you!!

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Notice the picture,
recall your SOH, CAH, TOA
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\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
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tan(\theta)=\cfrac{opposite}{adjacent}

you have,
opposite side, 165
adjacent side, 50
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that means, we'll need Mrs. tangent
thus 
\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50}
\\ \quad \\
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\\ \quad \\
\theta=tan^{-1}\left[ \cfrac{165}{50}\right]
\\ \uparrow  \\
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3 years ago
The diagram shows an isosceles triangle.
Lapatulllka [165]

Answer:

295°.It is such an easy triangle

4 0
3 years ago
Read 2 more answers
What the answers for those questions
Minchanka [31]

The answers are

11. c) 7x² +5x +8 remainder 7.

12. d) 6x² -6x +3 remainder 2x.

Step-by-step explanation:

Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.

Step 2; By dividing 6x^{4} +0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6x^{4} +6x³. We subtract this from 6x^{4} +0x³ and get -6x³. Now we add this with the -3x² in 6x^{4} +0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.

4 0
3 years ago
MathUp Evaluating Expressions
AysviL [449]

Since the question is incomplete, answer will be subjective. An example of Evaluating Expressions is find h + 8 − 9 j − h; where h = 7 and j = 5.

<h3>What is the Evaluating Expressions?</h3>

The evaluating expressions  is known to be a form of digital and printable board work that can help students in working on substituting values in terms of variables of an algebraic expression.

Evaluating the Expression below:

h + 8 − 9 j − h;

Therefore, where h = 7 and j = 5

7+ 8 − 9 (5) − 7.

SO: 7 + 8 - 45 -7

=  -37

Therefore the answer to the Evaluating Expression is -37.

Learn more about algebraic expression from

brainly.com/question/2164351

#SPJ1

6 0
1 year ago
State the slope and the y-intercept for the graph of each equation.
N76 [4]

Slope and y-intercept section:


<em>2. y=2x-2</em>

<em>Slope: 2</em>

<em>Y-intercept: -2</em>


<em>4. y=-x+3</em>

<em>Slope: -1</em>

<em>Y-intercept: 3</em>


<em>6. y=-1/3x+4</em>

<em>Slope: -1/3 (negative one third)</em>

<em>Y-intercept: 4</em>


<em>8. y+4x=2</em>

<em>Slope: -4</em>

<em>Y-intercept: 2</em>


Graphing section:

<em>y=mx+b where m = slope and b = y intercept</em>


<em>10. Graph a line with the slope of 1 and y-intercept of -4</em>

<em>slope form: y=1x+-4 </em>

<em>(first picture)</em>


<em>12. Graph a line with a slope of 1/3 and a y-intercept of 1.</em>

<em>slope form: y=1/3x+1</em>

<em>(second picture)</em>


<em>14. Graph y=3x-3</em>

<em>(third picture)</em>


<em>16. Graph y=4x-2</em>

<em>(fourth picture)</em>


<em>18. Graph y=2/3x-3</em>

<em>(fifth picture)</em>


Hope this helps! Please don't hesitate to ask any questions.

3 0
3 years ago
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