Notice the picture,
recall your SOH, CAH, TOA

you have,
opposite side, 165
adjacent side, 50
and the angle
that means, we'll need Mrs. tangent
thus
Answer:
295°.It is such an easy triangle
The answers are
11. c) 7x² +5x +8 remainder 7.
12. d) 6x² -6x +3 remainder 2x.
Step-by-step explanation:
Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.
Step 2; By dividing 6
+0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6
+6x³. We subtract this from 6
+0x³ and get -6x³. Now we add this with the -3x² in 6
+0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.
Since the question is incomplete, answer will be subjective. An example of Evaluating Expressions is find h + 8 − 9 j − h; where h = 7 and j = 5.
<h3>What is the Evaluating Expressions?</h3>
The evaluating expressions is known to be a form of digital and printable board work that can help students in working on substituting values in terms of variables of an algebraic expression.
Evaluating the Expression below:
h + 8 − 9 j − h;
Therefore, where h = 7 and j = 5
7+ 8 − 9 (5) − 7.
SO: 7 + 8 - 45 -7
= -37
Therefore the answer to the Evaluating Expression is -37.
Learn more about algebraic expression from
brainly.com/question/2164351
#SPJ1
Slope and y-intercept section:
<em>2. y=2x-2</em>
<em>Slope: 2</em>
<em>Y-intercept: -2</em>
<em>4. y=-x+3</em>
<em>Slope: -1</em>
<em>Y-intercept: 3</em>
<em>6. y=-1/3x+4</em>
<em>Slope: -1/3 (negative one third)</em>
<em>Y-intercept: 4</em>
<em>8. y+4x=2</em>
<em>Slope: -4</em>
<em>Y-intercept: 2</em>
Graphing section:
<em>y=mx+b where m = slope and b = y intercept</em>
<em>10. Graph a line with the slope of 1 and y-intercept of -4</em>
<em>slope form: y=1x+-4 </em>
<em>(first picture)</em>
<em>12. Graph a line with a slope of 1/3 and a y-intercept of 1.</em>
<em>slope form: y=1/3x+1</em>
<em>(second picture)</em>
<em>14. Graph y=3x-3</em>
<em>(third picture)</em>
<em>16. Graph y=4x-2</em>
<em>(fourth picture)</em>
<em>18. Graph y=2/3x-3</em>
<em>(fifth picture)</em>
Hope this helps! Please don't hesitate to ask any questions.