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3 years ago

Write these as a single term. 6a x 6b =

Mathematics

2 answers:

ahrayia [7]3 years ago

8 0

Answer:36ab

Step-by-step explanation:

Ber [7]3 years ago

3 0

Answer:

36ab

Step-by-step explanation:

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Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are both 3 inches.

Simora [160]

3^2+3^2=c^2 18=c^2 c=3sqrt2 Or 4.24 if you need a decimal answer

5 0

3 years ago

If r+9=42 does r+9-9=42+9

Step2247 [10]

Answer:

no i dont think so

Step-by-step explanation:

8 0

3 years ago

3 over 8 by x Solve "x" A: 5 over 64 B: 5 over 9 C: 1 over 6 D: 3 over 4

lapo4ka [179]

Answer: 1 is correct

2 is correct

3 is correct

4 is correct

5 is correct

6 is correct

7 is correct

8 is wrong it should be because you wouldn't add you would subtract it and the other number is negative so it would be x=-26

9 is correct

10 is correct

13 is correct

14 I think is correct

I think 15 is incorrect because if he says one less than twice the number of last year then I think you first should subtract 1 from 25 and then divide by 2 this would give you 17 packages

and I think 16 is correct too.

Hope this helped

Step-by-step explanation:

7 0

2 years ago

the digits 3,4,5,6,7,and 8 are randomly arranged to form a 3 digit number not repeating. find the probability that the number is

nadezda [96]

The answer would be 212,I can't completely explain why because I did it the long way which took me over an hour to do.

7 0

3 years ago

Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7

m_a_m_a [10]

Answer:

Option D.

Step-by-step explanation:

The given expression is

$\dfrac{(5ab)^3}{30a^{-6}b^{-7}}$

We need to find the expression, which is equivalent to the given expression.

The given expression can be rewritten as

$\dfrac{5^3a^3b^3}{30a^{-6}b^{-7}}$ $[\because (ab)^m=a^mb^m]$

$\dfrac{125}{30}\times \dfrac{a^3}{a^{-6}}\times \dfrac{b^3}{b^{-7}}$

$\dfrac{25}{6}\times a^{3-(-6)}\times b^{3-(-7)}$ $[\because \dfrac{a^m}{a^n}=a^{m-n}]$

$\dfrac{25}{6}\times a^{3+6}\times b^{3+7}$

$\dfrac{25a^9b^{10}}{6}$

Therefore, the correct option is D.

7 0

3 years ago