Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
C. 42.
Step-by-step explanation:
This is an arithmetic sequence with common difference d = 4 and first term a = -3.
Sum of n terms = (n/2)[2a + (n - 1)d]
Sum of six terms = (6/2)[2(-3) + (6 - 1)4]
= 3 * (-6 + 20)
= 42.
Answer: (-24,2)
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Work Shown:
The y coordinate stays the same. Only the x coordinate will change.
(1/4)*x = -6
x = -6*4
x = -24 is the new x coordinate
Plugging x = -24 into f((1/4)x) leads to f(-6) = 2
about 1 million robux cuz they each wortha bout a cent idk though on black market is cheaper
Answer:
im fairly certain the answer is C
Step-by-step explanation:
you take the base problem, 9-4n and plug in a number for n each time. 9-4(1), 9-4(2), 9-4(3)…
