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2 years ago

PLEASE HELP ME W THIS QUESTION

Mathematics

2 answers:

Lilit [14]2 years ago

4 0

Answer: (C) 5, 1, -3, -7, -11

Step-by-step explanation:

9 - 4n

n=1: 9 - 4(1) = 5

n=2: 9 - 4(2) = 1

n=3: 9 - 4(3) = -3

n=4: 9 - 4(4) = -7

n=5: 9 - 4(5) = -11

Note: -4n tells you that each term will decrease by 4.

FrozenT [24]2 years ago

3 0

Answer:

im fairly certain the answer is C

Step-by-step explanation:

you take the base problem, 9-4n and plug in a number for n each time. 9-4(1), 9-4(2), 9-4(3)…

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2 years ago

Which is the best approximation of the solutions to the system of equations graphed below?

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According to the direct inspection, we conclude that the best approximation of the two solutions to the system of quadratic equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>

Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the Cartesian plane.

According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two quadratic equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

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10 months ago

Don't steal points

Tomtit [17]

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The ceiling is lower than 3 meters.

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2 years ago

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The determined value of mean µ is 1.3 and variance σ² is 0.81.

What is mean and variance?

A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
The variance is calculated as the square root of the variance.

We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.

The table is attached as an image for reference.

Mean µ = ∑X P(X)

µ = 1.3

Variance (σ² ) = ∑ X² P(X)- (µ)²

= 2.5-(1.3)²

(σ² ) = 0.81

The determined value of mean µ is 1.3 and variance σ² is 0.81.

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1 year ago