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anygoal [31]
3 years ago
7

In 1774, Joseph Priestly discovered oxygen gas by heating mercury(II) oxide powder with focused sunlight through a lens. How man

y grams of HgO (216.59 g/mol) would be decomposed to produce 1.50 mol O2 ? A. 650. g HgO B. 325gHgO C. 162gHgO D. 3.00 g HgO

Chemistry
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

A. 650 g

Explanation:

The equation of the reaction is given as;

2 HgO(s) --> 2Hg(s)  + O2(l)

From the reaction;

2 mol of HgO produces 1 mol of O2

x mol of HgO would produce 1.50 mol of O2

2 = 1

x = 1.5

Solving for x;

x = 1.5 * 2 / 1 = 3 mol

Converting to mass;

Mass = Number of moles * Molar mass

Mass = 3 mol  * 216.59 g/mol

Mass = 649.77 g ≈ 650. g

Correct option is ;

A. 650 g

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A piece of material with a mass of 755 g is heated to 84.5 c and added to 50 g of water at 5
lana [24]
Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius

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