Answer:
Equation of line is y=(12/5)x+2
Step-by-step explanation:
The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.
Now, point X satisfies the equation. Plugging in the slope of the line we end up with
y=(12/5)*x+c, now to find c
-10=(12/5)*(-5)+c, c=2
Equation of line is y=(12/5)x+2
Answer:
Hello,
in order to simplify, i have taken the inverses functions
Step-by-step explanation:
![\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%20%7B%28-2x%5E2-x%2B1%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B%5Cfrac%7B-2x%5E3%7D%7B3%7D%20-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%2Bx%5D%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-2-3%2B12%7D%7B24%7D%20-%5Cdfrac%7B-5%7D%7B6%7D%20%5C%5C%5C%5C%5Cboxed%7B%3D%5Cdfrac%7B9%7D%7B8%7D%20%3D1.25%7D%5C%5C)
Answer:
$47
Step-by-step explanation:
If she spent 47, and had none after, she spent 47.
Answer:
A number decreased by 8 is less than 23.
Answer:
Option 3
y + 16 = 8(x + 2)
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
- x = 2, 4, 6, 8
- y = 16, 32, 48, 64
Now, Put the values in equation 1
y – 16 = 8(x – 2)
y – 16 = 8(x – 2)
16 – 16 = 8(2 – 2)
0 = 8
Here, L.H.S ≠ R.H.S
So, Option 1 is incorrect
Now, Put the values in equation 2
y – 16 = 8x – 2
y – 16 = 8x – 2
16 – 16 = 8(2) – 2
0 = 14
Here, L.H.S ≠ R.H.S
So, Option 1 is incorrect
Now, Put the values in equation 3
y + 16 = 8(x + 2)
y + 16 = 8(x + 2)
16 + 16 = 8(2 + 2)
32 = 8(4)
32 = 32
Here, L.H.S = R.H.S
Check other values of x and y
y + 16 = 8(x + 2)
32 + 16 = 8(4 + 2)
48 = 8(6)
48 = 48
Here, L.H.S = R.H.S
y + 16 = 8(x + 2)
48 + 16 = 8(6 + 2)
64 = 8(8)
64 = 64
Here, L.H.S = R.H.S
y + 16 = 8(x + 2)
64 + 16 = 8(8 + 2)
80 = 8(10)
80 = 80
Here, L.H.S = R.H.S
Thus, The equation 3 in point-slope from gives the plant's height at any time.
<u>-TheUnknownScientist 72</u>
