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IrinaVladis [17]
3 years ago
9

The perimeter of a square is 48 feet. What is the length of a side?

Mathematics
1 answer:
Anettt [7]3 years ago
4 0
12ft (48 divided by 4)
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One side of a triangular garden is x feet long. The other two sides of the garden are both 5 feet less than twice the length of
Gnoma [55]
A:  If the 1st side of the garden is x feet long then the other sides are 2x - 5.  The perimeter is simply the measure of the distance around the triangle, so the length of all three sides added up.  So the equation to find the perimeter (p) would be...

p = x + (2x+5) + (2x+5)
or
p = x + 2(2x+5)

This is actually an equation so the expression to represent perimeter would simply be...

x + 2(2x+5)

B:  Since we know the equation for the perimeter and we know that we have 40 feet of fencing, then the equation to find the left over fencing would just be the length of fencing minus the perimeter...

40 - x + 2(2x+5) = the leftover amount of fencing

so the expression is...

40 - x + 2(2x+5)


3 0
3 years ago
The sides of a rectangle are a number and 4 less than that same numbers. The perimeter is 56. Find the dimensions of the rectang
Rzqust [24]

Answer: find the answer in the explanation.

Step-by-step explanation:

You are given that the sides of a rectangle are a number and 4 less than that same numbers.

Let the length side = L

And width side = L - 4

The dimensions of the rectangle will be

Area = length × width

L × ( L - 4 )

Open the bracket

L^2 - 4L

The verbal expression here,

Perimeter = L + L + W + W

Substitute all the parameters into the formula

56 = L + L + L-4 + L-4

56 = 2L + 2L - 8

56 = 4L - 8

8 0
3 years ago
I need help in this!
In-s [12.5K]

For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that a is such that

\displaystyle\lim_{x\to0^-}g(x)=\lim_{x\to0^+}g(x)\iff\lim_{x\to0}ax=\lim_{x\to0}x^2-3x

Obviously, both limits are 0, so g is indeed continuous at x=0.

Now, for g to be differentiable everywhere, its derivative g' must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

g'(x)=\begin{cases}a&\text{for }x0\end{cases}

and at this time, we don't know what's going on at x=0, so we omit that case. We want g' to be continuous, so we require that

\displaystyle\lim_{x\to0^-}g'(x)=\lim_{x\to0^+}g'(x)\iff\lim_{x\to0}a=\lim_{x\to0}2x-3

from which it follows that a=-3.

3 0
2 years ago
Help please!! Branniest answer will be given!
Levart [38]

Answer:

30

Step-by-step explanation:

area of triangle 1/2 b×h

1/2 10×6=30m^×

Mark me brainliestt

6 0
2 years ago
What’s the answer to this problem?
Vedmedyk [2.9K]

Answer:

D 28x+40

Step-by-step explanation:

To find the perimeter, we add all the sides

2x+2x+5x+8+4x+10+5x+8+x+2+2x+7x+12 = P

Combine like terms

2x+2x+5x+4x+5x+x+2x+7x+10+8+8+2+12

28x +40

7 0
3 years ago
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