For algebra 2 please help <3
1 answer:
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Answer:
fog = 2√(x-1) + 1
Domain = [1, )
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1, )
Given:
The number is .
To find:
The a+bi form of given number.
Solution:
We have,
It can be written as
Here, real part is missing. So, it can be taken as 0.
So, a = 0 and .
Therefore, the a+bi form of given number is .