Beth's description of the transformation is incorrect
<h3>Complete question</h3>
Beth says that the graph of g(x)=x-5+1 is a translation of 5 units to the left and 1 unit up of f(x) = x. She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x). Is Beth's description of the transformation correct? Explain
<h3>How to determine the true statement?</h3>
The functions are given as:
g(x) = x - 5 + 1
f(x) = x
When the function f(x) is translated 5 units left, we have:
f(x + 5) = x + 5
When the above function is translated 1 unit up, we have:
f(x + 5) + 1 = x + 5 + 1
This means that the actual equation of g(x) should be
g(x) = x + 5 + 1
And not g(x) = x - 5 + 1
By comparison;
g(x) = x - 5 + 1 and g(x) = x + 5 + 1 are not the same
Hence, Beth's description of the transformation is incorrect
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Answer:
1/2
Step-by-step explanation:
Answer:
D or 3
Step-by-step explanation:
The equation you are saying is
-x = x-6
If you move both x's to one side, you get
-2x = -6
From this, you can simplify by dividing by -2
x=3, or D.
Hope this helped!
Answer:
12
Step-by-step explanation:
√(x2 - x1)² + (y2 - y1)²
√[4 - (-8)]² + (10 - 10)²
√(12)² + (0)²
√144 + 0
√144
=12
Answer:
No, this set of ordered pairs does not represent a function.
Explanation:
Functions have one y-value for a given x-value.
Ordered pairs are written (x, y).
In this set, when x=2, it has four y-values (4, 5, 6 and 7), so it cannot be a function.
