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stepladder [879]
3 years ago
11

Help As quick as possible

Mathematics
2 answers:
dolphi86 [110]3 years ago
7 0

Answer:

Answer d

Step-by-step explanation:

The answer is d r÷8

ddd [48]3 years ago
5 0

Answer:

r ÷8

Step-by-step explanation:

not 100% sure..........

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Solve for x, full steps
xxMikexx [17]

Answer:

x =34.56°

Step-by-step explanation:

adjacent/ hypotenuse =cosx

cosx = 14/17

x = cos^{-1}(14/17)

x =34.56°

3 0
3 years ago
Read 2 more answers
An equailateral triangle has a height of 52cm.Determine the length of each side to the nearest hundredth of a centimeter
neonofarm [45]
Each side is 52 cm. because equilateral triangles have equal lengths on each side. <span />
4 0
4 years ago
Read 2 more answers
A rectangular prism has a length of 1 1/4 centimeters, a width of 4 centimeters, and a height of 3 1/4 centimeters. What is the
Brut [27]
We know that

[volume of a prism]=length*<span>width*height
 </span><span>length=1 1/4 cm-------> (1*4+1)/4-------> 5/4 cm
</span><span>width = 4 cm
height=</span><span>3 1/4 cm---------> (3*4+1)/4------> 13/4 cm
</span>[volume of a prism]=(5/4)*4*13/4-----------> 65/4--------> 16.25 cm³

the answer is
the volume is 16.25 cm³  (16 1/4 cm³)
5 0
3 years ago
Q # 4 Solve the graph please &lt;6. , &lt;1. , &lt;2. ,&lt;4
juin [17]
The interior angel of 7 will be angel 4
∠7 + ∠4 = 180°
7 0
4 years ago
Solve x2 − 10x = −13.
aev [14]

Answer:

B

Step-by-step explanation:

First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial x^{2}-10x+13. We can now use the quadratic formula to solve.

Remember that the quadratic formula is

\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

Substitute the numbers from the equation into the formula.

\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}

Simplify:

\frac{10+/-\sqrt{100-52} }{2}

\frac{10+/-\sqrt{48} }{2}

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with 5+/-\sqrt{48}.

Hope this helps!

6 0
3 years ago
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