650×0.04=26 so 650+26= 676 soo the total would be $676.00
8 cups per minute.
How many cups in a pint? 2 cups in one pint.
8/2 = 4
Answer: 4 pints per minute
Answer:
hello your question is incomplete below is the complete question
Find the minimum sample size n needed to estimate μ For the given values of c, σ, and E. c=0.98, σ=6.5, and E=22 Assume that a preliminary sample has at least 30 members.
Answer : 48
Step-by-step explanation:
Given data:
E = 2.2,
std ( σ ) = 6.5
c ( level of confidence ) = 0.98
To find the minimum sample size
we have to first obtain the value of
note : a can be found using this relation :
( 1 - a ) = 0.98 ----- equation 1
a = 1 - 0.98 = 0.02
hence: a/2 = 0.01
This means that P( Z ≤ z ) = 0.99 the value of z can be found using the table of standard normal distribution. from the table the value of z = 2.33
P( Z ≤ 2.33 ) = 0.99
To obtain the sample size n

n =
= (6.88409)^2
Therefore n ≈ 48
we are rounding to the tenths place so we need to look at the hundredths place 5 and higher it goes up 4 and below it remains the same
15.50 thru 15.54 would round to 15.5
15.45 to 15.49 would round to 15.5
so 15.51 rounds to 15.5
15.49 rounds to 15.5
15.48 rounds to 15.5
Answer:
12x42=504
504/2=252
252
Step-by-step explanation: