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maxonik [38]
3 years ago
6

Using the 10% value to find 20% of 300

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
20% * 300 = 2 * (10% * 300) = 2*30 = 60
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The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? A. {5, 8} B. {-5, -8} C. {3, 8} D. {4,
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Answer:

Option D

The domain of the function is: {4, 7}

Step-by-step explanation:

We know that for polynomial functions like f(k) = k^2 + 2k + 1 its domain and its rank are all real numbers. However, for this case we are told that the function range is: the set {25, 64}

This means that the function is bounded.

Then the domain of f(k) are all possible values of k such that f(k) belongs to the interval {25, 64}.

To find the limit values of k then we do f(k) = 25

k^2 + 2k + 1 = 25

k^2 + 2k -24 = 0

Now we factor the expression:

(k + 6)(k-4) = 0

Then k = 4 and k = -6.

Now we do f(k) = 64

k ^ 2 + 2k +1 = 64\\\\k ^ 2 + 2k -63 = 0

We factor the expression:

(k + 9)(k-7) = 0

k = -9 and k = 7.

Finally we search between the options given an interval that matches.

The option that matches is option D {4, 7}

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