Question

Given: LaTeX: f\left(3\right)=7f ( 3 ) = 7 and LaTeX: \int_0^3f'\left(x\right)dx=18∫ 0 3 f ′ ( x ) d x = 18 , you can find the value of LaTeX: f\left(0\right)f ( 0 ) using the FTC in the following way:
LaTeX: \int_0^3f'\left(x\right)dx=f\left(x\right)\mid^3_0=f\left(3\right)-f\left(0\right)∫ 0 3 f ′ ( x ) d x = f ( x ) ∣ 0 3 = f ( 3 ) − f ( 0 )

LaTeX: 18=7-f\left(0\right)18 = 7 − f ( 0 )

LaTeX: f\left(0\right)=7-18=-11f ( 0 ) = 7 − 18 = − 11


True of False?

Answer 1

I’ll say it’s true because your left off with -11=-11 which is true